In the given reaction,[X] will be: | vedclass

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(D) The starting material is furfuryl chloride. In the presence of $NaCN$ and under $S_N1$ conditions,the $Cl^-$ ion leaves to form a resonance-stabil

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$(A)$ and $(C)$ both

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(D) The starting material is furfuryl chloride. In the presence of $NaCN$ and under $S_N1$ conditions,the $Cl^-$ ion leaves to form a resonance-stabilized carbocation,which is the furfuryl cation. This carbocation can undergo nucleophilic attack by $CN^-$ at the $CH_2$ position to give $2-$cyanomethylfuran (Option $A$). Additionally,due to the resonance stabilization,the positive charge can be delocalized onto the ring,allowing for attack at the ring carbon,leading to rearranged products like the one shown in Option $C$. Therefore,both $(A)$ and $(C)$ are possible products under these conditions.

List-$I$	List-$II$
$(A)$ Benzene	$1$. Phosgene
$(B)$ Ethylene	$2$. Silver mirror
$(C)$ Acetaldehyde	$3$. Mustard gas
$(D)$ Chloroform	$4$. $(4n + 2) \pi$ electrons
	$5$. Carbylamine

In the given reaction,$[X]$ will be:

Similar Questions

How many isomers are possible for the compound with the molecular formula $C_2BrClFI$?

Match the following lists:
List-$I$ List-$II$
$(A)$ Benzene $1$. Phosgene
$(B)$ Ethylene $2$. Silver mirror
$(C)$ Acetaldehyde $3$. Mustard gas
$(D)$ Chloroform $4$. $(4n + 2) \pi$ electrons
$5$. Carbylamine

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